Which gives the ans as 4044 09 ms.
A boat of mass 50kg is at rest. A boy of mass 50kg walks from the bow to the stern. The above figure represents the phenomenon described in the problem. Let v be the velocity of the person and boat after the stone is thrown.
Therefore velocity of boat man 1520045 03375 ms. Lets set this equal to the increase of stones momentum. M 190 v.
Now for my final center of mass. The velocity of the boat is 1ms. The velocity of the person and the boat after the throwing the stone is Option 1 200 ms NORTH Option 2 121 ms SOUTH.
New and used models for sale. Now boat will displace in opposite direction for making the position of center of mass undisturbed. Speed of man in boat15 ms.
M260kg person initially on right end of boat. According the first Newtons law the center of gravity is at rest or in uniform motion. Applying the law of conservation of momentum.
190 v 20 v 20 190. While gravity is 1 times the weight of the object is pushing the object up weight pulling the object down a buoyancy force of 40 mg. A boat of mass 40 kg is at rest A dog of mass 4 kg moves in the boat with a velocity of 10ms what is the velo.