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A boat of mass 50kg is at rest. To find the solution is used the fact that the resultant of the external forces acting on the system boat-man is in every moment equal to zero. Lets determine the sum of mass of person and boat. A boy of mass 50kg walks from the bow to the stern.

Applying the law of conservation of momentum. The kinetic energy of the other mass is a 324 J b 486 J c 256 J d 524 J. A dog of mass 5kg is standing on a flat boat of mass 20 kgsuch that it is 10m away from the shore the dog then moves 4 m towards the shore and finally haltsfind.

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The velocity of the person and the boat after the throwing the stone is Option 1 200 ms NORTH Option 2 121 ms SOUTH. The above figure represents the phenomenon described in the problem. Assuming that the center of mass of a person is elevated by approximately Δh050m.

While gravity is 1 times the weight of the object is pushing the object up weight pulling the object down a buoyancy force of 40 mg. A semicircular disc of radius r is released from rest from the position shown if no stooping occurs between the disc and the horizontal surface in the expression for the angular velocity ω reached by the disc when its kinetic energy is maximum is ω x y z t g r a d s e c. 14060 x v60 x 15.

An object of mass 50 kg is released from rest from a boat into the water and allowed to sink. 190 v 20 v 20 190. Suppose this displacement is x and its speed is v.